Integrand size = 15, antiderivative size = 98 \[ \int \log ^3\left (\frac {c x^2}{(b+a x)^2}\right ) \, dx=x \log ^3\left (\frac {c x^2}{(b+a x)^2}\right )+\frac {6 b \log ^2\left (\frac {c x^2}{(b+a x)^2}\right ) \log \left (\frac {b}{b+a x}\right )}{a}+\frac {24 b \log \left (\frac {c x^2}{(b+a x)^2}\right ) \operatorname {PolyLog}\left (2,\frac {a x}{b+a x}\right )}{a}-\frac {48 b \operatorname {PolyLog}\left (3,\frac {a x}{b+a x}\right )}{a} \]
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Time = 0.07 (sec) , antiderivative size = 98, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.333, Rules used = {2536, 2552, 2354, 2421, 6724} \[ \int \log ^3\left (\frac {c x^2}{(b+a x)^2}\right ) \, dx=\frac {24 b \operatorname {PolyLog}\left (2,\frac {a x}{b+a x}\right ) \log \left (\frac {c x^2}{(a x+b)^2}\right )}{a}+x \log ^3\left (\frac {c x^2}{(a x+b)^2}\right )+\frac {6 b \log \left (\frac {b}{a x+b}\right ) \log ^2\left (\frac {c x^2}{(a x+b)^2}\right )}{a}-\frac {48 b \operatorname {PolyLog}\left (3,\frac {a x}{b+a x}\right )}{a} \]
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Rule 2354
Rule 2421
Rule 2536
Rule 2552
Rule 6724
Rubi steps \begin{align*} \text {integral}& = x \log ^3\left (\frac {c x^2}{(b+a x)^2}\right )-(6 b) \int \frac {\log ^2\left (\frac {c x^2}{(b+a x)^2}\right )}{b+a x} \, dx \\ & = x \log ^3\left (\frac {c x^2}{(b+a x)^2}\right )-(6 b) \text {Subst}\left (\int \frac {\log ^2\left (c x^2\right )}{1-a x} \, dx,x,\frac {x}{b+a x}\right ) \\ & = x \log ^3\left (\frac {c x^2}{(b+a x)^2}\right )+\frac {6 b \log ^2\left (\frac {c x^2}{(b+a x)^2}\right ) \log \left (\frac {b}{b+a x}\right )}{a}-\frac {(24 b) \text {Subst}\left (\int \frac {\log \left (c x^2\right ) \log (1-a x)}{x} \, dx,x,\frac {x}{b+a x}\right )}{a} \\ & = x \log ^3\left (\frac {c x^2}{(b+a x)^2}\right )+\frac {6 b \log ^2\left (\frac {c x^2}{(b+a x)^2}\right ) \log \left (\frac {b}{b+a x}\right )}{a}+\frac {24 b \log \left (\frac {c x^2}{(b+a x)^2}\right ) \text {Li}_2\left (\frac {a x}{b+a x}\right )}{a}-\frac {(48 b) \text {Subst}\left (\int \frac {\text {Li}_2(a x)}{x} \, dx,x,\frac {x}{b+a x}\right )}{a} \\ & = x \log ^3\left (\frac {c x^2}{(b+a x)^2}\right )+\frac {6 b \log ^2\left (\frac {c x^2}{(b+a x)^2}\right ) \log \left (\frac {b}{b+a x}\right )}{a}+\frac {24 b \log \left (\frac {c x^2}{(b+a x)^2}\right ) \text {Li}_2\left (\frac {a x}{b+a x}\right )}{a}-\frac {48 b \text {Li}_3\left (\frac {a x}{b+a x}\right )}{a} \\ \end{align*}
Time = 0.02 (sec) , antiderivative size = 98, normalized size of antiderivative = 1.00 \[ \int \log ^3\left (\frac {c x^2}{(b+a x)^2}\right ) \, dx=x \log ^3\left (\frac {c x^2}{(b+a x)^2}\right )+\frac {6 b \log ^2\left (\frac {c x^2}{(b+a x)^2}\right ) \log \left (\frac {b}{b+a x}\right )}{a}+\frac {24 b \log \left (\frac {c x^2}{(b+a x)^2}\right ) \operatorname {PolyLog}\left (2,\frac {a x}{b+a x}\right )}{a}-\frac {48 b \operatorname {PolyLog}\left (3,\frac {a x}{b+a x}\right )}{a} \]
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\[\int \ln \left (\frac {c \,x^{2}}{\left (a x +b \right )^{2}}\right )^{3}d x\]
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\[ \int \log ^3\left (\frac {c x^2}{(b+a x)^2}\right ) \, dx=\int { \log \left (\frac {c x^{2}}{{\left (a x + b\right )}^{2}}\right )^{3} \,d x } \]
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\[ \int \log ^3\left (\frac {c x^2}{(b+a x)^2}\right ) \, dx=- 6 b \int \frac {\log {\left (\frac {c x^{2}}{a^{2} x^{2} + 2 a b x + b^{2}} \right )}^{2}}{a x + b}\, dx + x \log {\left (\frac {c x^{2}}{\left (a x + b\right )^{2}} \right )}^{3} \]
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\[ \int \log ^3\left (\frac {c x^2}{(b+a x)^2}\right ) \, dx=\int { \log \left (\frac {c x^{2}}{{\left (a x + b\right )}^{2}}\right )^{3} \,d x } \]
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\[ \int \log ^3\left (\frac {c x^2}{(b+a x)^2}\right ) \, dx=\int { \log \left (\frac {c x^{2}}{{\left (a x + b\right )}^{2}}\right )^{3} \,d x } \]
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Timed out. \[ \int \log ^3\left (\frac {c x^2}{(b+a x)^2}\right ) \, dx=\int {\ln \left (\frac {c\,x^2}{{\left (b+a\,x\right )}^2}\right )}^3 \,d x \]
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